H_BOIL_LEE_KANG_KIM
This function calculates the boiling heat transfer coefficient for corrugated plate channels using the Lee-Kang-Kim correlation. It uses quality, equivalent diameter, liquid/gas properties, mass flow, and heat flux to evaluate two-phase boiling intensity.
The model uses piecewise expressions based on flow-regime indicators and can be represented as:
h = f\left(\frac{Re_g}{Re_l}, Bo, X_{tt}\right)\frac{k_l}{D_{eq}}
where X_{tt} is the Martinelli-type parameter and the result is returned in W/m^2/K.
Excel Usage
=H_BOIL_LEE_KANG_KIM(m, x, D_eq, rhol, rhog, mul, mug, kl, Hvap, q, A_channel_flow)
m(float, required): Mass flow rate (kg/s).x(float, required): Quality at the specific point (-).D_eq(float, required): Equivalent diameter of the channels (m).rhol(float, required): Density of the liquid (kg/m^3).rhog(float, required): Density of the gas (kg/m^3).mul(float, required): Viscosity of the liquid (Pa*s).mug(float, required): Viscosity of the gas (Pa*s).kl(float, required): Thermal conductivity of liquid (W/m/K).Hvap(float, required): Heat of vaporization (J/kg).q(float, required): Heat flux (W/m^2).A_channel_flow(float, required): Channel flow area (m^2).
Returns (float): Boiling heat transfer coefficient (W/m^2/K).
Example 1: Lee Kang Kim correlation example case
Inputs:
| m | x | D_eq | rhol | rhog | mul | mug | kl | Hvap | q | A_channel_flow |
|---|---|---|---|---|---|---|---|---|---|---|
| 0.00003 | 0.4 | 0.002 | 567 | 18.09 | 0.000156 | 0.000009 | 0.086 | 900000 | 100000 | 0.0003 |
Excel formula:
=H_BOIL_LEE_KANG_KIM(0.00003, 0.4, 0.002, 567, 18.09, 0.000156, 0.000009, 0.086, 900000, 100000, 0.0003)
Expected output:
1229.63
Example 2: Lee Kang Kim correlation at low quality
Inputs:
| m | x | D_eq | rhol | rhog | mul | mug | kl | Hvap | q | A_channel_flow |
|---|---|---|---|---|---|---|---|---|---|---|
| 0.00004 | 0.2 | 0.0018 | 600 | 16 | 0.00018 | 0.00001 | 0.09 | 850000 | 90000 | 0.00028 |
Excel formula:
=H_BOIL_LEE_KANG_KIM(0.00004, 0.2, 0.0018, 600, 16, 0.00018, 0.00001, 0.09, 850000, 90000, 0.00028)
Expected output:
4321.25
Example 3: Lee Kang Kim correlation at higher heat flux
Inputs:
| m | x | D_eq | rhol | rhog | mul | mug | kl | Hvap | q | A_channel_flow |
|---|---|---|---|---|---|---|---|---|---|---|
| 0.00005 | 0.55 | 0.0022 | 520 | 20 | 0.00014 | 0.000008 | 0.08 | 950000 | 140000 | 0.00032 |
Excel formula:
=H_BOIL_LEE_KANG_KIM(0.00005, 0.55, 0.0022, 520, 20, 0.00014, 0.000008, 0.08, 950000, 140000, 0.00032)
Expected output:
572.31
Example 4: Lee Kang Kim correlation at mid heat flux
Inputs:
| m | x | D_eq | rhol | rhog | mul | mug | kl | Hvap | q | A_channel_flow |
|---|---|---|---|---|---|---|---|---|---|---|
| 0.000025 | 0.35 | 0.0019 | 580 | 12 | 0.00017 | 0.000009 | 0.085 | 870000 | 95000 | 0.00029 |
Excel formula:
=H_BOIL_LEE_KANG_KIM(0.000025, 0.35, 0.0019, 580, 12, 0.00017, 0.000009, 0.085, 870000, 95000, 0.00029)
Expected output:
1311.66
Python Code
Show Code
from ht.boiling_plate import h_boiling_Lee_Kang_Kim as ht_h_boiling_Lee_Kang_Kim
def h_boil_Lee_Kang_Kim(m, x, D_eq, rhol, rhog, mul, mug, kl, Hvap, q, A_channel_flow):
"""
Calculate boiling heat transfer coefficient using Lee Kang Kim correlation.
See: https://ht.readthedocs.io/en/latest/ht.boiling_plate.html
This example function is provided as-is without any representation of accuracy.
Args:
m (float): Mass flow rate (kg/s).
x (float): Quality at the specific point (-).
D_eq (float): Equivalent diameter of the channels (m).
rhol (float): Density of the liquid (kg/m^3).
rhog (float): Density of the gas (kg/m^3).
mul (float): Viscosity of the liquid (Pa*s).
mug (float): Viscosity of the gas (Pa*s).
kl (float): Thermal conductivity of liquid (W/m/K).
Hvap (float): Heat of vaporization (J/kg).
q (float): Heat flux (W/m^2).
A_channel_flow (float): Channel flow area (m^2).
Returns:
float: Boiling heat transfer coefficient (W/m^2/K).
"""
try:
result = ht_h_boiling_Lee_Kang_Kim(m, x, D_eq, rhol, rhog, mul, mug, kl, Hvap, q, A_channel_flow)
return result
except Exception as e:
return f"Error: {str(e)}"