HUGHMARK
Computes a laminar two-phase heat transfer coefficient in tube flow using the Hughmark correlation, which is based on entry-region behavior and void-fraction-adjusted liquid contribution.
The model returns heat transfer coefficient from the Nusselt relationship:
h = \frac{Nu\,k_l}{D}
with Nu formed from empirical dependence on mass flow, liquid thermal properties, tube length, and optional viscosity correction.
Excel Usage
=HUGHMARK(m, x, alpha, D, L, Cpl, kl, mu_b, mu_w)
m(float, required): Mass flow rate (kg/s).x(float, required): Quality at the tube interval (-).alpha(float, required): Void fraction in the tube (-).D(float, required): Tube diameter (m).L(float, required): Tube length (m).Cpl(float, required): Liquid heat capacity at constant pressure (J/kg/K).kl(float, required): Liquid thermal conductivity (W/m/K).mu_b(float, optional, default: null): Liquid viscosity at bulk conditions (Pa*s).mu_w(float, optional, default: null): Liquid viscosity at wall temperature (Pa*s).
Returns (float): Heat transfer coefficient (W/m^2/K).
Example 1: Hughmark example
Inputs:
| m | x | alpha | D | L | Cpl | kl | mu_b | mu_w |
|---|---|---|---|---|---|---|---|---|
| 1 | 0.9 | 0.9 | 0.3 | 0.5 | 2300 | 0.6 | 0.001 | 0.0012 |
Excel formula:
=HUGHMARK(1, 0.9, 0.9, 0.3, 0.5, 2300, 0.6, 0.001, 0.0012)
Expected output:
212.741
Example 2: Without wall viscosity correction
Inputs:
| m | x | alpha | D | L | Cpl | kl | mu_b |
|---|---|---|---|---|---|---|---|
| 0.6 | 0.4 | 0.7 | 0.05 | 1 | 4180 | 0.6 | 0.001 |
Excel formula:
=HUGHMARK(0.6, 0.4, 0.7, 0.05, 1, 4180, 0.6, 0.001)
Expected output:
778.145
Example 3: Lower void fraction
Inputs:
| m | x | alpha | D | L | Cpl | kl | mu_b | mu_w |
|---|---|---|---|---|---|---|---|---|
| 0.4 | 0.2 | 0.4 | 0.04 | 0.8 | 3900 | 0.55 | 0.0011 | 0.0013 |
Excel formula:
=HUGHMARK(0.4, 0.2, 0.4, 0.04, 0.8, 3900, 0.55, 0.0011, 0.0013)
Expected output:
509.305
Example 4: Longer tube length
Inputs:
| m | x | alpha | D | L | Cpl | kl | mu_b | mu_w |
|---|---|---|---|---|---|---|---|---|
| 0.8 | 0.6 | 0.8 | 0.06 | 2 | 3600 | 0.52 | 0.0009 | 0.001 |
Excel formula:
=HUGHMARK(0.8, 0.6, 0.8, 0.06, 2, 3600, 0.52, 0.0009, 0.001)
Expected output:
591.242
Python Code
Show Code
from ht.conv_two_phase import Hughmark as ht_Hughmark
def Hughmark(m, x, alpha, D, L, Cpl, kl, mu_b=None, mu_w=None):
"""
Calculate two-phase laminar heat transfer coefficient using the Hughmark correlation.
See: https://ht.readthedocs.io/en/latest/ht.conv_two_phase.html
This example function is provided as-is without any representation of accuracy.
Args:
m (float): Mass flow rate (kg/s).
x (float): Quality at the tube interval (-).
alpha (float): Void fraction in the tube (-).
D (float): Tube diameter (m).
L (float): Tube length (m).
Cpl (float): Liquid heat capacity at constant pressure (J/kg/K).
kl (float): Liquid thermal conductivity (W/m/K).
mu_b (float, optional): Liquid viscosity at bulk conditions (Pa*s). Default is None.
mu_w (float, optional): Liquid viscosity at wall temperature (Pa*s). Default is None.
Returns:
float: Heat transfer coefficient (W/m^2/K).
"""
try:
return ht_Hughmark(
m=m,
x=x,
alpha=alpha,
D=D,
L=L,
Cpl=Cpl,
kl=kl,
mu_b=mu_b,
mu_w=mu_w,
)
except Exception as e:
return f"Error: {str(e)}"Online Calculator
Mass flow rate (kg/s).
Quality at the tube interval (-).
Void fraction in the tube (-).
Tube diameter (m).
Tube length (m).
Liquid heat capacity at constant pressure (J/kg/K).
Liquid thermal conductivity (W/m/K).
Liquid viscosity at bulk conditions (Pa*s).
Liquid viscosity at wall temperature (Pa*s).